Dipole Moment
Trending Questions
- 0.4×N4
- 0.25×NA
- 4×NA
- 0.025×NA
(BF3, NF3 and NH3)
- BF3>NF3>NH3
- NF2>BF3>NH3
- NH3>NF3>BF3
- NH3>BF3>NF3
What is the SI unit of dipole moment?
- NH3
- PH3
- AsH3
- SbH3
If the AB4 molecule is a polar molecule, a possible geometry of AB4 is:
Square planar
Tetrahedral
Square pyramidal
Rectangular planar
What are polar and non polar covalent compounds?
What is the IUPAC name of ?
- Boron is a solid and nitrogen is a gas in free state
- BF3 is planar while NF3 is pyramidal in shape
- Boron is a metalloid while nitrogen is a non-metal
- Atomic size of Boron is smaller than that of nitrogen
What is the structure of ?
Which of the following will have a meso isomer also.
2-hydroxypropanoic acid
2, 3-dichlorobutane
2, 3-dichloropentane
2-chlorobutane
If B–Cl bond has a dipole moment, explain why BCl3 molecule has zero dipole moment.
Among the following the maximum covalent character is shown by the compound
A) FeCl2. B) SnCl2. C) AlCl3. D) MgCl2.
Explain in detail.
Explain why BeH2 molecule has a zero dipole moment although the Be–H bonds are polar.
The shape of molecule is:
- SiF4
- BF3
- PF3
- PF5
- The dipole moment of NF3 is zero
- The dipole moment of NF3 is less than NH3
- The dipole moment of NF3 is more than NH3
- The dipole moment of NH3 is zero
- I < IV < II < III
- IV < I < II < III
- IV < I < III < II
- IV < II < I < III
- HI<HBr<HCl<HF
- HBr<HI<HCl<HF
- HI<HBr<HF<HCl
- HF<HCl<HBr<HI
Although both CO2 and H2O are triatomic molecules, the shape of H2O molecule is bent while that of CO2 is linear. Explain this on the basis of dipole moment.
- C6H6(benzene)
- CCl4
- All of these
- BF3
- CH3Cl>CH3F>CH3Br>CH3I
- CH3F>CH3Cl>CH3I>CH3Br
- CH3F>CH3Cl>CH3Br>CH3I
- CH3Cl>CH3Br>CH3I>CH3F
What is the shape of using VSEPR Theory?
What will be the formula of the compound if all the atoms from one of the faces of the cube are removed?
- Cu8Ag4Au3
- Cu3Ag3Au4
- Cu8Ag3Au3
- Cu3Ag4Au3
Which of the following elements can be involved in bonding?
Nitrogen
Carbon
Boron
Phosphorus
Given: cos 105o = − 0.25
- 1.617×10−10 esu
- 1.617×10−10 C
- 1.167×10−12 esu
- 1.167×10−15 esu
- 10.83×1022
- 21.68×1023
- 7.22×1023
- 15.22×1023
(BF3, NF3 and NH3)
- BF3>NF3>NH3
- NF2>BF3>NH3
- NH3>NF3>BF3
- NH3>BF3>NF3
- 83%
- 25%
- 17%
- 90%
- θ = 90o
- θ = 120o
- θ = 150o
- θ = 180o