Effect on Conductance in Titration
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Q.
The conductometric titration curve for CH3COOH against NaOH can be given as
Q. Which of the following expressions correctly represents the equivalent conductance at infinite dilution of Al2(SO4)3? Given that ΛoAl3+ and ΛoSO2−4 are the equivalent conductances at infinite dilution of the respective ions.
- 2ΛoAl3++3ΛoSO2−4
- ΛoAl3++ΛoSO2−4
- (ΛoAl3++ΛoSO2−4)×6
- 13ΛoAl3++12ΛoSO2−4
Q. The values of Λ0eq for NH4Cl, NaOH and NaCl are 149.74, 248.1 and 126.4 ohm−1 cm2 eq−1 respectively. The value of Λ0eq(NH4OH) is :
- 371.44
- 271.44
- 171.44
- Cannot be calculated from the data given
Q. Choose the correct option(s) when conductometric titration of a strong acid vs. weak base (titrant) is carried out:
- Conductance increases up to the equivalence point.
- Conductance decreases up to the equivalence point.
- Beyond equivalence point , conduction starts decreasing sharply.
- Beyond equivalence point , conduction remains almost constant.
Q. Which of the following statement(s) is/are correct regarding the plot between Λm vs √C?
Λm - Molar conductivity
C - concentration of electrolyte
Λm - Molar conductivity
C - concentration of electrolyte
- Λm increase slowly with increase in dilution for strong electrolyte
- Λm increase steeply as dilution is increased, for weak electrolyte
- The plot curve is a straight line with negative slope for weak electrolyte
- Both (a) and (b)
Q. Conductometric titration curve of an equimolar mixture of HCl and HCN with NaOH (aq) can be given as
Q. Match the titration graphs
(1) NaOH + NH4OH vs HCl
(2) CH3 COOH vs NaOH
(3)HCl vs NaOH
(4)CH3 COOH vs NH4OH
a)
b)
c)
d)
(1) NaOH + NH4OH vs HCl
(2) CH3 COOH vs NaOH
(3)HCl vs NaOH
(4)CH3 COOH vs NH4OH
a)
b)
c)
d)
- 1-(c) 2-(a) 3-(d) 4-(b)
- 1-(b) 2-(c) 3-(d) 4-(a)
- 1-(c) 2-(b) 3-(a) 4-(d)
- 1-(b) 2-(a) 3-(d) 4-(c)
Q. Assertion: when NaOH is added to the HCl solution, the conductance of the solution decreases right upto the equivalence point and then increases.
Reason: At starting, fast moving to ions replaced by relatively slower moving Na⊕ ions and after the equivalence point, as OH− start increases conductance increases.
Reason: At starting, fast moving to ions replaced by relatively slower moving Na⊕ ions and after the equivalence point, as OH− start increases conductance increases.
- Statement 1 & 2 are correct and statement 2 is correct explanation of statement 1
- Statement 1 & 2 are correct but statement 2 is not correct explanation of statement 1
- Statement 1 is true, statement 2 is false
- Statement 1 is false and statement 2 is true
Q. Heat of neutralisation of weak acid and strong base is less than the heat of neutralisation of strong acid and strong base due to:
- Incomplete dissociation of weak acid
- Energy has to be spent for the total dissociation of weak acid
- Salt of weak acid and strong base is not stable
- Incomplete neutralisation of weak acid
Q. When SO2 is passed through acidified K2Cr2O7 solution.
(a) The solution turns green
(b) The solution is decolourized
(c) Reduction of SO2 takes place
(d) Green ppt of Cr2(SO4)3 is formed
(a) The solution turns green
(b) The solution is decolourized
(c) Reduction of SO2 takes place
(d) Green ppt of Cr2(SO4)3 is formed
Q. AgNO3 (aq.) was added to an aqueous KCI solution gradually and the conductivity of the solution was measured. The plot of conductance (A)versus the volume of AgNO3 is.
- P
- Q
- R
- S
Q. Choose the correct option, when conductometric titration of a strong acid vs. weak base (titrant) is carried out:
- Conductance increases up to the equivalence point.
- Conductance remains constant up to the equivalence point.
- Beyond equivalence point , conduction starts decreasing sharply.
- Beyond equivalence point , conduction remains almost constant.
Q. A solution containing Cu2+ and C2O2−4 ions is titrated with 20 mL of M4 KMnO4 solution in acidic medium. The resulting solution is treated with excess of KI after neutralization. The evolved I2 is then absorbed is 25 mL of M10 hypo solution. Which of the following statements is/are correct?
- The difference in the number of mmol of Cu2+ and C2O2−4 ions in the solution is 10 mmol
- The difference in the number of mmol of Cu2+ and C2O2−4 ions in the solution is 22.5 mmol
- The equivalent weight of Cu2+ ions in the titration with KI is equal to the atomic weight of Cu2+
- The equivalent weight of KI in the titration is M2 where M is the molecular weight of KI
Q.
What is meant by ‘demineralised’ water and how can it be obtained?