Photoelectric Effect
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(Mass of electron = 9×10−31 kg, Velocity of light = 3×108 ms−1, Plank's constant = 6.626×10−34 Js, Charge of electron = 1.6×10−19 J eV−1)
- 3.1 eV
- 0.9 eV
- 4.0 eV
- 2.1 eV
When electromagnetic radiation of wavelength 300 nm falls on the surface of sodium, electrons are emitted with a kinetic energy of 1.68×105J mol−1. What is the maximum wavelength that will cause a photoelectron to be emitted?
- λ=320 nm
- λ=449.7 nm
- λ=526 nm
- λ=518 nm
Calculate energy of one mole of photons of radiation whose frequency as 5 × 1014Hz.
499.31 KJ
199.51 KJ
299.31 KJ
399.31 KJ
- 4.969×1020
- 2.012×1020
- 4.969×1018
- 2.012×1021
Calculate the velocity of the electron in the first Bohr orbit of the hydrogen atom (Given, r = a)
The work function for caesium atom is 1.9 eV. Calculate (a) the threshold wavelength and (b) the threshold frequency of the radiation. If the caesium element is irradiated with a wavelength 500 nm, calculate the kinetic energy and the velocity of the ejected photoelectron.
A photon of wavelength 4 × 10–7 m strikes on the metal surface, the work function of the metal is 2.13 eV. Calculate
(i) the energy of the photon (eV),
(ii) the kinetic energy of the emission, and
(iii) the velocity of the photoelectron (1 eV= 1.6020 × 10–19 J).
- doubled
- halved
- more than doubled
- increases but less than doubled
How does the quantum theory explain the photoelectric effect?
- 4 eV
- 5.5 eV
- 4.5 eV
- 5 eV
- 1.2 × 1014 Hz
- 8 × 1015 Hz
- 4 × 1012 Hz
- 1.2 × 1016 Hz
Statement- 2: The number of photoelectrons ejected increases with increase in intensity of light.
- Both the statements are true.
- Statement- 1 is true and statement- 2 is false.
- Both the statements are false.
- Statement- 1 is false and statement- 2 is true.
- As the intensity increases, photoelectric effect may increase
- As the intensity increases, photoelectric effect decreases.
- As the intensity decreases, photoelectric effect increases.
- No effect
An electron of mass and a proton of mass are moving at the same speed. The ratio of their de Broglie wavelength will be:
- 3.31 × 10−19 J
- 1.13 × 10−18 J
- 7.12 × 10−19 J
- None of These
- 6.604×103∘A
- 6.604∘A
- 3.905×103∘A
- 3.905∘A
Electrons are emitted with zero velocity from a metal surface when it is exposed to radiation of wavelength 6800 Å. Calculate threshold frequency ( v0 ) and work function ( W0 ) of the metal.
- 5900 oA
- 2700 oA
- 1700 oA
- 3100 oA
- 4.64 eV
- 6.65 eV
- 8.45 eV
- 10.25 eV
A Light of wavelength λ shines on a metal surface with intensity X, and the metal emits Y electrons per second of average energy Z. What will happen to Y and Z If X is doubled?
Y will be doubled and Z will become half.
Y will remain same and Z will be doubled.
Both Y and Z will be doubled.
Y will be doubled but Z will remain same.
Then x=
When an electromagnetic radiation of wavelength 310 nm falls on the surface of sodium metal, electrons are emitted with K.Emax = 1.5 eV. Determine the work function Wo of metal.
- 2.5 eV
- 5.2 eV
- 10.5 eV
- 12.5 eV
- The slope of the line is equal to the Planck's constant.
- The threshold frequency is ν1
- As the frequency of the incident wavelength increases beyond the threshold frequency, the kinetic energy of the photoelectrons decreases.
- It is impossible to obtain such a graph.
- 1×1014Hz
- 2×1014Hz
- 1×1015Hz
- 2×1015Hz
- Wavelength of incident light
- Frequency of incident light
- Velocity of incident light
- Atomic mass of an element.
(Planck's constant (h) = 6.6×10−34 J s)
- 1.2×10−18 J
- 1.2×10−20 J
- 6×10−19 J
- 6×10−12 J
- 1.988×10−19 J
- 4.567×10−19 J
- 1.988×10−16 J
- 4.567×10−16 J
- halved
- doubled
- unchanged
- increases but more than the double of previous kinetic energy
- Emin=3.84×10−19J
- Emin=2.31×105J
- Emin=4.42×10−19J
- Emin=3.78×10−19J