Physical Properties of Haloarenes
Trending Questions
Q. Give reasons:
1. thionyl chloride is preferred reagent for converting ethanol to chloroethane
2. Tert-butyl bromide has lower bioling point than n-butyl bromide
3. although alkyl halides are polar in nature they are not soluble in water
1. thionyl chloride is preferred reagent for converting ethanol to chloroethane
2. Tert-butyl bromide has lower bioling point than n-butyl bromide
3. although alkyl halides are polar in nature they are not soluble in water
Q. Out of NH3 and N2 which will have larger 'a' value and larger 'b' value ?
Q. Rearrange the following compounds in the increasing order of their boiling points :
CH3−CHO, CH3−CH2−OH, CH3−CH2−CH3
CH3−CHO, CH3−CH2−OH, CH3−CH2−CH3
Q. CH3COC2H5-^{naoh/I2}-->X(yellow ppt.) -^{Ag}-->Y(g)
Q. Haloalkanes and haloarenes don't carry that much weightage but alcohols, phenols and ether do. So can I skip haloalkanes and jump to alcohols due to time constraints ? please give me some idea
Q. 57. 0.1mole Bacl2 is mixed with 0.3mole Na3PO4.Calculate the maximum amount of (BaPO4)2 formed.
Q.
Why does have a lower boiling point than ?
Q. Which of the following compounds has the highest melting point?
- bromobenzene
- o-dibromobenzene
- m-dibromobenzene
- p-dibromobenzene
Q. 8 Which among the following show tautomers? (1) Alcohols (2) Phenol (3) Ethers (4) Anisole
Q. Which of the following complex represent maximum stability ? (1) \lbrack Co(CN)6\rbrack3– (2) \lbrack Co(H2O)6\rbrack3+ (3) \lbrack Co(CN)6\rbrack4– (4) \lbrack Co(C2O4)3\rbrack3–
Q. Assertion :Statement-I : boiling point of alkyl halide increases with increase in molecular weight.
Because Reason: Statement-II : boiling point of alkyl halides are in the order RI>RBr>RCl>RF.
Because Reason: Statement-II : boiling point of alkyl halides are in the order RI>RBr>RCl>RF.
- (A)Statement-I is true, Statement-II is true ; Statement-II is correct explanation for Statement-I.
- (B)Statement-I is true, Statement-II is true ; Statement-II is NOT a correct explanation for Statement-I.
- (C)Statement-I is true, Statement-II is false.
- (D)Statement-I is false, Statement-II is true.
Q. Arrange the given set of compounds in order of increasing boiling point:
I. 1-chloropropane
II. Isopropyl chloride
III. 1-chlorobutane
I. 1-chloropropane
II. Isopropyl chloride
III. 1-chlorobutane
- II<III<I
- II<I<III
- I<II<III
- III<I<III
Q. Arrange the following compounds in order of increasing dipole moment I. Toluene II. m-dichlorobenzene III. o-dichlorobenzene IV. p-dichlorobenzene
- IV < II < I < III
- IV < I < II < III
- IV < I < III < II
- I < IV < II < III
Q. Which of the following has the least value of dipole moment?
(correct answer +1, wrong answer -0.25)
(correct answer +1, wrong answer -0.25)
- CCl4
- CHCl3
- CH3CH2OH
- CH3COCH3
Q. Arrange the following compounds in the increasing order of their boiling points:
CH3CH2CHOI CH3CH2CH2OHII
(CH3)3CO−K+III C2H5OC2H5IV
CH3CH2CHOI CH3CH2CH2OHII
(CH3)3CO−K+III C2H5OC2H5IV
Q. Which is the correct increasing order of boiling points of the following compounds?
1 - Iodobutane, 1 - Bromobutane, 1 - Chlorobutane, Butane
1 - Iodobutane, 1 - Bromobutane, 1 - Chlorobutane, Butane
- Butane < 1 - Chlorobutane < 1 - Bromobutane < 1 - Iodobutane
- 1 - Iodobutane < 1 - Bromobutane < 1 - Chlorobutane < Butane
- Butane < 1 - Iodobutane < 1 - Bromobutane < 1 - Chlorobutane
- Butane < 1 - Chlorobutane < 1 - Iodobutane < 1 - Bromobutane
Q. Arrange the following compounds in order of increasing dipole moment I. Toluene II. m-dichlorobenzene III. o-dichlorobenzene IV. p-dichlorobenzene
- I<IV<II<III
- IV<I<II<III
- IV<I<III<II
- IV<II<I<III
Q.
(II) CH3CH2CH2CH2Br
(II) CH3CH2CH2CH2Br
Arrange the following compounds in increasing order of their boiling points:
- (I) < (II) < (III)
- (III) < (I) < (II)
- (II) < (I) < (III)
- (III) < (II) < (I)
Q. Which is the correct increasing order of boiling points of the following compounds?
1 - Bromoethane, 1 - Bromobutane, 1 - Bromobutane, Bromobenzene
1 - Bromoethane, 1 - Bromobutane, 1 - Bromobutane, Bromobenzene
- Bromobenzene < 1 - Bromoethane < 1 - Bromopropane < 1 - Bromobutane
- 1 - Bromopropane < 1 - Bromobutane < 1 - Bromoethane < Bromobenzene
- 1 - Bromoethane < 1 - Bromopropane < 1 - Bromobutane < Bromobenzene
- Bromobenzene < 1 - Bromobutane < 1 - Bromopropane < 1 - Bromoethane
Q. Which alkyl-halide has maximum density?
- C2H5I
- C3H7I
- CH3Br
- CH3I
Q. Among the following compounds which has the highest boiling point?
- All have same boiling point
- 2-Bromopentane
- 3-Bromopentane
- 1-Bromopentane
Q. Arrange the following compounds in increasing order of their boiling points.
I. CH3CH2CH2Br
II. CH3CH2CH2CH2Br
III. (CH3)2CHCH2Br
IV. (CH3)3CBr
I. CH3CH2CH2Br
II. CH3CH2CH2CH2Br
III. (CH3)2CHCH2Br
IV. (CH3)3CBr
- II<I<III<IV
- IV<III<II<I
- I<IV<III<II
- III<I<IV<II
Q. Why does p-dichlorobenzene have a higher m.p than its o- and m- isomers?
Q. Arrange the following compounds in increasing order of boiling points.
I: 3-methyl pentane II: 3-chloropentane
III: 3-bromopentane IV: 3, 3-dichloropentane
I: 3-methyl pentane II: 3-chloropentane
III: 3-bromopentane IV: 3, 3-dichloropentane
- I<III<II<IV
- I<IV<III<II
- I<II<III<IV
- I<III<IV<II
Q. Arrange each set of compounds, in the order of increasing boiling points.
(i) Bromomethane, Bromoform, Chloromethane, Dibromomethane
Q. Arrange the following compounds in decreasing order of their boiling points :
(i)CH3Br
(ii)CH3CH2Br
(iii)CH3CH2CH2Br
(iv)CH3CH2CH2CH2Br
(i)CH3Br
(ii)CH3CH2Br
(iii)CH3CH2CH2Br
(iv)CH3CH2CH2CH2Br
- (iii) > (iv) > (i) > (ii)
- (i) > (ii) > (iii) > (iv)
- (iv) > (iii) > (ii) > (i)
- (i) > (iii) > (ii) > (iv)
Q. For a given alkyl group, the boiling points of alkyl halides follow the order:
- RI>RBr>RCl
- RCl>RBr>RI
- RI>RCl>RBr
- RBr>RI>RCl
Q. Dipole moment of CO2 is zero because –
- C contain lone pair electrons
- Electro negativity of C and O are unequal
- is pyramidal
- is linear
Q. Rearrange the following compounds in the increasing order of their boiling points:
CH3−CHO, CH3−CH2−OH, CH3−CH2−CH3
CH3−CHO, CH3−CH2−OH, CH3−CH2−CH3
Q. Statement 1: Paradichlorobenzene has higher melting point and solubility than that of ortho and meta forms.
Statement 2: Para isomer has symmetrical structure and can easily pack closely in crystal structure.
- Statement 1 is correct and statement 2 is wrong.
- Both Statement 1 and Statement 2 are correct and Statement 2 is correct explanation for Statement 1.
- Both Statement 1 and Statement 2 are correct and Statement 2 is not correct explanation for Statement 1.
- Statement 1 is wrong and statement 2 is correct.