Synthesis of Secondary and Tertiary Amines
Trending Questions
Q. A hydrocarbon A(C4H8) on reaction withHCl gives a compound B(C4H9Cl) which on reaction with 1 mole of NH3 gives a compound C(C4H11N). On reacting with NaNO2 and HCl (low temperature) followed by treatment with water, compound C yields optically active alcohol(s). Ozonolysis of A(1 mole) gives 2 moles of acetaldehyde.
The compound C is:
The compound C is:
- Butan-2-amine
- N, N-dimethylethanamine
- Diethylamine
- Butylamine
Q. Assertion: Benzaldehyde and formaldehyde undergo Cannizzaro reaction.
Reason: Benzaldehyde are almost as reactive as formaldehyde.
Reason: Benzaldehyde are almost as reactive as formaldehyde.
- Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
- Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
- Assertion is correct but Reason is incorrect
- Both Assertation and Reason are incorrect
Q. What is the best reagent to convert nitrile to primary amine?
Q. 10. order of reactivity of different aryl halides through nucleophilic aromatic substitution mechanism
Q. Ammonolysis of Alkyl halides followed by the treatment with NaOH solution can be used to prepare primary, secondary and tertiary amines. The purpose of NaOH in the reaction is
<!--td {border: 1px solid #cccccc;}br {mso-data-placement:same-cell;}--> JEE MAIN 2021
<!--td {border: 1px solid #cccccc;}br {mso-data-placement:same-cell;}--> JEE MAIN 2021
- To activate NH3 used in the reaction
- To increase the reactivity of alkyl halide
- To remove basic impurities
- To remove acidic impurities
Q. What happens when ethylamine is made to react with excess formic acid and formaldehyde?
- The mechanism involves reductive amination
- The intermediate is a secondary amine
- The final product is a tertiary amine
- This reaction is called Eschweiler-Clarke methylation
Q. Based on the reaction given above, choose the correct options:
- The products are stereoisomers
- The products are constitutional isomers
- The reaction proceeds via electrophilic aromatic substitution
- The mechanism involves a benzyne intermediate
Q. A group which deactivates the benzene ring towards electrophilic substitution but directs the reaction at ortho and para position:
- −NH2
- −Cl
- −NO2
- −C2H5
Q. A hydrocarbon A(C4H8) on reaction withHCl gives a compound B(C4H9Cl) which on reaction with 1 mole of NH3 gives a compound C(C4H11N). On reacting with NaNO2 and HCl (low temperature) followed by treatment with water, compound C yields optically active alcohol(s). Ozonolysis of A(1 mole) gives 2 moles of acetaldehyde.
The compound C is:
The compound C is:
- Butan-2-amine
- Diethylamine
- Butylamine
- N, N-dimethylethanamine
Q.
Primary alkyl halide C4H9Br (X) reacts with alc.KOH to give compound (Y). Compound (Y) reacts with HBr to give compound (Z) which is an isomer of (X). When (X) react with Na metal it gives compound (P).
Primary alkyl halide C4H9Br (X) reacts with alc.KOH to give compound (Y). Compound (Y) reacts with HBr to give compound (Z) which is an isomer of (X). When (X) react with Na metal it gives compound (P).
Hence compound (X), (Y), (Z) and (P) respectively are :
- CH3−CH|CH3−CH2Br; CH3CH=CHCH3 ; CH3−CH|Br−CH2CH3 ; C6H12
- CH3−CH|CH3−CH2Br; CH3−C|CH3=CH2 ; CH3−Br|C|CH3−CH3 ; C8H18
- CH3CH2CH2CH2Br ; CH3CH=CHCH3 ; CH3−CH|Br−CH2CH3 ; C5H10
- CH3−CH|Br−CH2CH3; CH3CH=CHCH3 ; CH3CH2CH2CH2Br ; C7H14
Q. For the reaction 2A⟶B+3C; if −d[A]dt=k1[A]2;d[B]dt=k2[B]2;d[A]dt=k3[A]2 the correct relation between k1, k2 and k3
- k1=k2=k3
- 4k1=k2=3k3
- 2k1=k2=3k3
- k12=k2=k33
Q. CH3CH2OH is converted into CH3CHO in the presence of:
- Na2Cr2O7 and NaOH
- Na2Cr2O7 and aq.H2SO4
- NaOH
- Fe in presence of NaOH
Q. What is the formula of quick lime?
Q. Match the column I with column II and mark the appropriate choice.
Column I | Column II | ||
(A) | Aniline | (i) | Can be made by Gabriel phthalimide reaction |
(B) | N-Methylaniline | (ii) | Undergoes electrophilic substitution reaction with HNO2 |
(C) | N, N-Dimethylaniline | (iii) | Forms yellow oily product with HNO2 |
(D) | Benzylamine | (iv) | Gives azo dye test |
- (A)→(iv), (B)→(iii), (C)→(ii), (D)→(i)
- (A)→(ii), (B)→(iv), (C)→(i), (D)→(iii)
- (A)→(iii), (B)→(i), (C)→(iv), (D)→(ii)
- (A)→(i), (B)→(ii), (C)→(iii), (D)→(iv)
Q.
how to convert Ethyl isocyanide to ethyl amine.
Q. Which one of the following compounds most readily undergoes substitution by SN2 mechanism?
- A
- B
- D
- C
Q. In a nucleophilic substitution reaction:
R−Br+Cl−DMF−−−→R−Cl+Br−
Which one of the following undergoes complete inversion of configuration?
- C6H5CHC6H5Br
- C6H5CH2Br
- C6H5CH(CH3)Br
- C6H5CCH3C6H5Br
Q. In the below shown reaction sequence, the compound B formed is :
CH3CH2CH2OH PCl3−−−→A alc. KOH−−−−−−→ B
CH3CH2CH2OH PCl3−−−→A alc. KOH−−−−−−→ B
- propane
- propene
- propanol
- propyne
Q. Butanedial+Ammonium carbonate△−→P
Then:
Then:
- P is aromatic
- P is antiaromatic
- P on reaction with chloroform and sodium hydroxide gives:
- P on reaction with chloroform and sodium hydroxide gives:
Q. One mole of a hydrocarbon having molecular weight 78 is subjected to ozonolysis and H2O2 formed in the reaction is not removed from the site of reaction. The product obtained on treatment with Ca2+ ions gives 384g of calcium oxalate. The hydrocarbon is
- CH3−C≡C−C≡C−CH3
- CH3≡C−CH2−CH2−C≡CH
- CH≡C−CH2−C≡−CH3
- C6H6
Q. What happens when ethylamine is made to react with excess formic acid and formaldehyde?
- The intermediate is a secondary amine
- The final product is a tertiary amine
- This reaction is called Eschweiler-Clarke methylation
- The mechanism involves reductive amination
Q. The following statements are correct under certain conditions. Mention the conditions.
Cl2 substitutes hydrogen atoms of a molecule of methane.
Cl2 substitutes hydrogen atoms of a molecule of methane.
Q. Caustic potash is potassium hydroxide (KOH).
- True
- False
Q. CH3−CH2−CH=CH2+CH3OHH⊕→CH3−CH2−C|OCH3H−CH3
What is nucleophile in first step?
- CH3OH
- 1-butene
- H2O
- CH3−O−CH3
Q. Primary amines can be exclusively formed by ammonolysis of alkyl halides.
- True
- False
Q. Predict substitution/elimination products that might be obtained when each of the given alkyl halides are treated with CH3ONa in ethanol. Include stereochemistry where appropriate.
Q. At 10000C,
Zn(s)+12→ZnO(s);△G0=−360kJmol−1
C(1)+12O2(g);△G0=−460kJmol−1
The correct statement is:
Zn(s)+12→ZnO(s);△G0=−360kJmol−1
C(1)+12O2(g);△G0=−460kJmol−1
The correct statement is:
- zinc can be oxidised by carbon monoxide
- zinc blend is produced during the reaction
- zinc oxide can be reduced by graphite
- zinc can be oxidised by graphite
Q. Match the reactions listed in List 1 with the color of the precipitate(s) listed in List 2.
Q. CH2=CH2+Br2→CH2Br−CH2Br, is an example of:
- addition reaction
- substitution reaction
- elimination reaction
- molecular rearrangement
Q. The organic compound which undergoes substitution reaction is?
- C2H4
- C10H18
- C2H6
- C2H2