sp3 Hybridisation
Trending Questions
Boron Trifluorideis a non polar molecule whereas ammonia is a polar molecule. The difference in polarity is related to the fact that
has no hydrogen bonding and does
is triangular planar and is pyramidal
is Lewis base and is Lewis acid
None of the above.
What is the hybridization of ?
- Maximum six hydrogen atoms can lie in a plane
- Maximum six atoms can lie in a plane
- Bridging Hb−B−Hb bonds are stronger than terminal B−Ht bonds
- Terminal Ht−B−Ht bond angle is greater than bridging Hb−B−Hb bond angle.
Suggest reasons why the B–F bond lengths in BF3 (130 pm) and BF−4 (143 pm) differ.
What is the difference between dsp3 and sp3d hybridization?
The state of hybridization of boron and oxygen atoms in boric acid(H3BO3) are respectively:
sp3 and sp3
sp2 and sp3
sp3 and sp2
sp2 and sp2
- NH+4
- PCl3
- SCl2
- NH3
- Trigonal bipyramidal
- Octahedral
- Both (b) and (c)
- Tetrahedral
- four
- six
- zero
- two
Name a molecule that has a trigonal pyramidal shape.
Apart from tetrahedral geometry, another possible geometry for CH4 is square planar with the four H atoms at the corners of the square and the C atom at its centre. Explain why CH4 is not square planar?
- Number of lone pairs at central atoms are same in both molecular ions
- Hybridization of central atoms in both ions are same
- Both are polar species
- Both are planar species
CN−, NO+, O2, O+2, O2+2
(i) | XeF2 | (a) | Central atom is sp3 hybridised and has a bent shape. |
(ii) | N−3 | (b) | Central atom is sp3d2 hybridised and has an octahedral shape. |
(iii) | PCl−6 | (c) | Central atom is sp hybridised and has a linear shape. |
(iv) | ICl+2 | (d) | Central atom is sp3d hybridised and has a linear shape. |
- (i - a), (ii - b), (iii - c), (iv - d)
- (i - d), (ii - b), (iii - d), (iv - c)
- (i - b), (ii - c), (iii - a), (iv - d)
- (i - d), (ii - c), (iii - b), (iv - a)
List-I List-II
(Species) (Hybrid orbitals)
(a) SF4 (i) sp3d2
(b) IF5 (ii) d2sp3
(c) NO+2 (iii) sp3d
(d) NH+4 (iv) sp3
(v) sp
Choose the correct answer from the options given below :
- (a)−(ii), (b)−(i), (c)−(iv), (d)−(v)
- (a)−(iv), (b)−(iii), (c)−(ii), (d)−(v)
- (a)−(i), (b)−(ii), (c)−(v), (d)−(iii)
- (a)−(iii), (b)−(i), (c)−(v), (d)−(iv)
- 180o, 109.5o
- 109.5o, 109.5o
- 104.5o, 180o
- 109.5o, 180o
- sp3d2, sp3d
- sp3d2, sp3d2
- dsp2, sp3
- sp3d, sp3d2
What is the difference between a stereogenic center and a chiral center?
A) 2-Chloro-3-methylpentane
2) - Write structure of the following compounds:
A) 1-Chloro-4-ethylcyclohexane
3) - Write structure of the following compounds:
C) 4-tert. Butyl-3-iodoheptane
4) - Write structure of the following compounds:
D) 1, 4-Dibromobut-2-ene
5) - Write structure of the following compounds:
D) 1-Bromo-4-sec. butyl-2-methylbenzene.
The property of Carbon to form long chains or rings are -
Catenation
Polymerisation
Cracking
Hydrogenation
Write the number of and atoms in a molecule of Propane.
- There are two bridging hydrogen atoms.
- Each boron atom forms four bonds
- All hydrogen atoms are not in same plane
- Each boron atom is in sp3 hybridized state
Arrange the following compounds in increasing order of dipole moment. CH3CH2CH3, CH3CH2NH2, CH3CH2OH.
- sp3, sp2, sp2
- sp2, sp2, sp2
- sp3, sp3, sp2
- sp3, sp2, sp
Predict the shape of and
- 3
- 4
- 2
- 5
(i) In diborane 12 valence e− are involved in bonding
(ii) In diborane, two boron and four terminal hydrogen, lie in the same plane.
(iii) Diborane has ethane-like structure
(iv) In diborane, bridging bonds are 3-centre 2- electron bond
- In covalent (gaseous) state, each Cl atom has a hybridisation of sp3 in Cl2O6
- Cl2O6 exists as ClO+2 and ClO−4 in ionic form
- In ionic form of Cl2O6, hybridisation of Cl atoms is sp2 and sp3
- In ionic form of Cl2O6, hybridisation of both the Cl atoms is sp3
- SO3, CO2−3
- NO−2, ClO−2
- BeCl2, HCN
- XeF2, SnCl2