Coupling
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A vibration magnetometer placed in a magnetic meridian has a small bar magnet. The magnet executes oscillations with a time period of in the earths horizontal magnetic field of microteslas. When a horizontal field of microteslas is produced opposite to the earths field by placing a current-carrying wire, the new time period of the magnet will be
- 5μ0I18πR
- μ0I36πR
- 5μ0I36πR
- 5μ0I9πR
A conducting circular loop is placed in a uniform magnetic field with its plane perpendicular to the magnetic field. The radius of the loop starts shrinking at . What is the induced emf in the loop if the radius is ?
- M = L1 / L2
- M = L1L2
- M = √L1L2
- M = (L1L2)2
- 23
- 2
- 12
- 32
- 1.6π μV
- 3.2π μV
- 4.8π μV
- 0.8π μV
- 3
- 13
- √3
- 1√3
- 1.0×10−5 T
- 1.0×10−7 T
- 1.5×10−7 T
- 1.5×10−5 T
- Increased by 72%
- Decreased by 72%
- Increased by 36%
- Decreased by 36%
- R2
- Zero
- R
- R√2
The mutual inductance between two planar concentric rings of radii r1 and r2 (with r1>>r2) placed in air is given by
μ0πr222r1
μ0π(r1+r2)22r1
μ0π(r1+r2)22r2
μ0πr212r2
Obtain the expression for mutual inductance of a pair of long coaxial solenoids each of length l and radii r1 and r2(r2>>r1). Total number of turns in the two solenoids are N1 and N2 respectively.
- n2√2
- n√2
- 2√2 n
- √2n
A circular loop of radius 0.0157 m carries a current of 2.0 amp .The magnetic field at the center of the loop is
- 684
- 290
- 395
- 768
- The total current passing through the cross section of the wire is I=πka42
- The total current passing through the cross section of the wire is I=3πka42
- The magnetic field at a distance r>a is B=μ0ka44r
- The magnetic field at a distance r<a is B=μ0kr34
The inner and outer coils of the two long co-axial solenoids are the same length and have radii of , as well as different numbers of turns per unit length, , respectively. The inner-self-inductance coils and mutual inductance are compared as follows:
- 4×10−6 T
- 2×10−8 T
- 0.8×10−7 T
- 0.4×10−8 T
The magnet of vibration magnetometer is heated so as to reduce its magnetic moment by 36%. By doing this the periodic time of the magnetometer will
Decreases by 64%
Increases by 36%
Decreases by 25%
Increases by 25%
- μ0I2R(1+1π) ⨀
- μ0I2R(1+1π) ⨂
- μ0I2R(1−1π) ⨀
- μ0I2R(1−1π) ⨂
- μoI4(r1r22)⊗
- μoI4(1r2)⊙
- μoI4(r1+r2r1r2)⊗
- μoI4(r1+r2r1r2)⊙
- √2μ0i3πa⊙
- √2μ0i3πa⊗
- √2μ0iπa⊙
- √2μ0iπa⊗
[Horizontal component of the earth's magnetic field is 24 μT]
- 1.2 Am2
- 12 Am2
- 0.12 Am2
- 120 Am2
- greater than in wire c
- less than in wire b
- equal to that in wire d
- less than in wire d
[Horizontal component of the earth's magnetic field is 24 μT]
- 12 Am2
- 120 Am2
- 1.2 Am2
- 0.12 Am2
What is Henry?