Nuclear Fission
Trending Questions
- 1.15×1013 Joule
- 0.5×1013 Joule
- 4.5×1016 Joule
- 4.5×1013 Joule
The power obtained in a reactor using U235 disintegration is 1000 kW . What is the mass decay of U235 per hour ?
- 1
- 2
- 3
- 4
- TA>TB (if mA>mB)
- TATB=(rArB)32
- TA=TB
- TA>TB (if rA>rB)
Calculate the energy released by 1 g of natural uranium assuming 200 MeV is released in each fission event and that the fissionable isotope 235U has an abundance of 0.7 % by weight in natural uranium.
- 5×1017
- 5×1018
- 5×1016
- 5×1019
The radioactive decay of uranium into thorium is represented by the equation
23892U→ 23490Th+x
What is x?
a neutron
an alpha particle
an electron
a proton
- 5.5 MeV
- 5.4 MeV
- 2.0 MeV
- 6.5 MeV
A bomb of 12 kg explodes into two pieces of masses 4 kg and 8 kg. The velocity of 8kg mass is 6 m/sec. The kinetic energy of the other mass is
32 J
24 J
288 J
48 J
- Eb+Ec=Ea
- Eb+Ec>Ea
- Eb+Ec<Ea
- Eb.Ec=Ea
The energy released by the fission of one uranium atom is 200 MeV. The number of fissions per second required to produce 3.2 W of power is
107
1010
1015
1017
- 214 MeV
- 119 MeV
- 2047 MeV
- 1142 MeV
131I is an isotope of Iodine that β− decays to an isotope of Xenon with a half-life of 8 days. A small amount of a serum labelled with 131I is injected into the blood of a person. The activity of the amount of 131I injected was 2.4×105 Becquerel (Bq). It is known that the injected serum will get distributed uniformly in the blood stream in less than half an hour. After 11.5 hours, 2.5 ml of blood is drawn from the person's body, and gives an activity of 115 Bq. The total volume of blood in the person's body, in liters is approximately _______.
(Avogadro number, NA=6.023×1023)
- 8.202×1014 J
- 8.202×1012 J
- 8.202×1010 J
- 8.202×108 J
U236→X111+Y122+30n1
If the binding energies per nucleon of X111, Y122 and U236 are 8.6 MeV, 8.5 MeVand 7.6 MeV respectively, then the energy released in the reaction will be
- 498 MeV
- 398 MeV
- 298 MeV
- 198 MeV
A) Calculate electrostatic potential energy of neutron and compare it with its mass 939 MeV.
B) Calculate electrostatic potential energy of proton and compare it with its mass 939 MeV.
- l2
- l3/2
- l1/2
- l
A240→B100+C140+Q(energy).
Let binding energy per nucleon of nucleus A, B and C is 7.6 MeV, 8.1 MeV and 8.1 MeV respectively. Value of Q is : (Approximately)
- 20 MeV
- 220 MeV
- 120 MeV
- 240MeV
- 200 KeV
- 2 MeV
- 200 MeV
- 2000 MeV
- 407 days
- 410 days
- 421 days
- 414 days
- 140
- 148
- 144
- 142
- 9438 Sr
- 14054 Xe
- 9941 Nb
- 8936 Kr
1H2+1H3→2He4+0n1
The repulsive potential energy between the two fusing nuclei is 7.7×10−14 J. The temperature to which the gas must be heated is nearly
(Boltzmen constant K=1.38×10−23 JK−1)
- 103 K
- 3.7×105 K
- 107 K
- 3.7×109 K
92U235+0n1→ 38Sr90+_____
- 57X142+ 30n1
- 54X145+ 30n1
- 54X143+ 30n1
- 54X142+ 0n1