Wave Speed expression
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- Points D, E and F have upward (positive) velocity.
- Points A, B and H have downward (negative) velocity.
- Points A and E have minimum velocity.
- Point C and G have zero velocity.
What is the formula for calculating wave velocity?
What are the effects of the velocity of sound on changing pressure and temperature?
What is the effect of rise in temperature on the velocity of sound?
→B(x, t)=[1.2×10−7sin(0.5×103x+1.5×1011t)^k] T
The instantaneous electric field →E corresponding to →B is (speed of light c=3×108 ms−1)
- →E(x, t)=[−36sin(0.5×103x+1.5×1011t)^j] Vm
- →E(x, t)=[−36sin(1×103x+0.5×1011t)^j] Vm
- →E(x, t)=[36sin(0.5×103x+1.5×1011t)^k] Vm
- →E(x, t)=[36sin(1×103x+1.5×1011t)^i] Vm
- c=1πa
- c=πa
- b=ac
- b=1ac
An electromagnetic wave of intensity falls on a metal surface on an area and is completely absorbed by it. Find the force exerted by the beam.
A hollow pipe of length is closed at one end. At its open end, a long uniform string is vibrating in its second harmonic and it resonates with the fundamental frequency of the pipe. If the tension in the wire is and the speed of sound is , the mass of the string is
A 4.0 kg block is suspended from the ceiling of an elevator through a string having a linear mass density of 19.2×10 kg m−1. Find the speed (with respect to the string) with which a wave pulse can proceed on the string if the elevator accelerates up at the rate of 2.0 ms−2. Take g=10 ms−2.
(ε0=8.85×10−12 C2N−1m−2)
- 8.31 T
- 5.88 T
- 2.77×10−8 T
- 1.96×10−8 T
- 5 m/s, 2.24 m/s
- 10 m/s, 3.23 m/s
- 7.5 m/s, 1.2 m/s
- 2.25 m/s, 5 m/s
- √L2g
- √2Lg
- √Lg
- √4Lg
y(x, t)=Asin2x(vt−xλ)
If the maximum particle velocity is three times the wave velocity, the wavelength λ of the wave is
- πA3
- 2πA3
- πA
- πA2
A heavy ball is suspended from the ceiling of a motor car through a light string. A transverse pulse travels at a speed of 60 cm s−1 when the car accelerates on a horizontal road. Find the acceleration of the car. Take g=10 ms−1.
- 400 Hz
- 50 Hz
- 300 Hz
- 200 Hz
- 0.4 s
- 0.04 s
- 20 s
- 0.06 s
y=0.01sin2π(10t−x)→y and x are in meters and t in seconds. Then
- Closest points on the string which differ in phase by 60∘ are (1/6) m apart.
- The speed of the wave is 10 m/s
- The phase of a certain point on the string changes by 120∘ in (1/20) seconds.
- Maximum particles velocity is π/4 m/s.
- 0
- π4
- π2
- π
Consider two points lying at a distance of and from an oscillating source. If the periodic time of oscillation is and the velocity of the wave produced is , then what will be the phase difference between the two points?
(The speed of light =3×108 m/s)
- 6×104 N/C
- 4×104 N/C
- 3×104 N/C
- 4.5×104 N/C
How do you increase the amplitude of a wave?
- 2.7×1012 T
- 9.0×10−3 T
- 3.0×10−4 T
- 3.0×10−5 T
y=4sin[π2(8t−x8)]. If x and y are measured in cm and t is in seconds, then velocity of wave is :
- 64 cm/s along −x direction
- 32 cm/s along −x direction
- 32 cm/s along +x direction
- 64 cm/s along +x direction
- n4
- √2n
- n
- n√2
A wave propagates on a string in the positive x-direction at a velocity v. The shape of the string at t=t0 is given by g(x, t0)=A sin(xa) . Write the wave equation for a general time t.
A string of mass is under the tension of . The length of the stretched string is . If the transverse jerk is stuck at one end of the string, how long does the disturbance take to reach the other end?
- 0.156 T
- 0.256 T
- 0.356 T
- 0.656 T
A sound wave of frequency 100 Hz is travelling in air. The speed of sound in air is 350ms−1. (a) By how much is the phase changed at a given point in 2.5 ms? (b) What is the phase difference at a given instant between two points separated by a distance of 10.0 cm along the direction of propagation?
- 12, 14, 16, ...
- 1, 2, 3, ...
- 1, 13, 15, ...
- 1, 3, 5, ...