Kepler's Law
Trending Questions
If the earth is at one-fourth of its present distance from the sun, the duration of the year will be
Half the present year
One-eighth the present year
One-fourth the present year
One-sixth the present year
The angular momentum of a planet of mass moving around the sun in an elliptical orbit is . The magnitude of the areal velocity of the planet is
For the planet-sun system identify the correct statement
The angular momentum of the planet is conserved
The total kinetic energy of the system is conserved
The momentum of the planet is conserved
All of the above
Two satellites S1 and S2 revolve round a planet in coplanar circular orbits in the same sense. Their periods of revolution are 1 hour and 8 hours respectively. The radius of the orbit of S1=104km When S2 is closest to S1 find speed of S2 relative to S2 and the angular speed of S1 actually observed by an astronaut at S1.
-4.91 ×10−4 rad s−1
-2.91 ×10−4 rad s−1
2.3 ×10−4 rad s−1
-6.00 ×10−8 rad s−1
- True
- False
Two planets of equal mass orbit a much more massive star (figure). Planet m1 moves in a circular orbit of radius 1×108 km with period 2 year. Planet m2 moves in an elliptical orbit with closest distance r1=1×108 km and farthest distance r21.8×108km, as shown. Using the fact that mean radius of an elliptical orbit is the length of the semi-major axis, find the period of m′2 s orbit.
2.1 year
3.31 year
4.12 year
5.24 year
Venus looks brighter than other planets because
It is heavier than other planets
It has higher density than other planets
It is closer to the earth than other planets
It has no atmosphere
- −4G
- −60G
- −20G
- +2G
- √x
- x
- x√x
- x2
- π rad/hr
- π/3 rad/hr
- 2π rad/hr
- π/2 rad/hr
- 11√2 kms−1
- 22 kms−1
- 11 kms−1
- 11√2 kms−1
- True
- False
- A
- B
- C
- D
The period of revolution of an earth satellite close to surface of earth is 90 min. The time period of another satellite in an orbit at a distance of three times the radius of earth from its surface will be
90√80min
360 min
720 min
270 min
- αβ
- α2β
- α3β
- 2αβ
The time period of a satellite in a circular orbit around a planet is independent of______.
the mass of the planet
the radius of the planet
the mass of the satellite
- density of the planet
Mass M is divided into two parts xM and (1 − x)M. For a given separation, the value of x for which the gravitational attraction between the two pieces becomes maximum is
12
35
1
2
- C
- A
- B
- D
The distance of neptune and saturn from sun are nearly 1013 and 1012 meters respectively. Assuming that they move in circular orbits, their periodic times will be in the ratio
√10
100
10√10
1√10
A planet moves around the sun. At a given point P, it is closest from the sun at a distance d1 and has a speed v1. At another point Q, when it is farthest from the sun at a distance d2, its speed will be
d21v1d22
d2v1d1
d1v1d2
d22v1d21
- r2
- r2√2
- r(4)1/3
- r(2)1/3
The period of a satellite in a circular orbit of radius R is T, the period of another satellite in a circular orbit of radius 4R is
4T
T4
8T
T8
The distance of neptune and saturn from sun are nearly 1013 and 1012 meters respectively. Assuming that they move in circular orbits, their periodic times will be in the ratio
√10
100
10√10
1√10
- √x
- x
- x√x
- x2
- A
- B
- C
- D
- Speed is greatest when comet is closest to the Sun
- In half motion, comet is retarded and in the other half motion, comet is accelerated
- Angular momentum of comet about any point is constant
- Motion is in plane
- Conservation of kinetic energy
- Conservation of linear momentum
- Conservation of angular momentum
- None of these
If the distance between the earth and the sun were reduced to half its present value, Then the number of days in one year would have been
65
129
183
730
- π rad/hr
- π/3 rad/hr
- 2π rad/hr
- π/2 rad/hr
In planetary motion the areal velocity of position vector of a planet depends on angular velocity (ω) and the distance of the planet from sun (r). If so the correct relation for areal velocity is
dAdt∝ ω r
dAdt∝ ω2 r
dAdt∝ ω r2
dAdt∝ √ω r