Newton's Laws of Motion
Trending Questions
Q. A body of mass m1 collides head on elastically with a stationary body of mass m2. If velocities of m1 before and after the collision are v and –v/3 respectively then the value of m1/m2 is
- 0.5
- 4
- 1
- 2
Q. In the figure shown below, mA=2 kg and mB=3 kg. A force F=40 N is applied on 2 kg block as shown. Find the acceleration of COM of the system. (Neglect friction everywhere and assume the string to be inextensible)
- 1.2 m/s2
- 1 m/s2
- 2.4 m/s2
- 2 m/s2
Q. Two blocks of masses 5 kg and 2 kg are placed at rest on a frictionless surface and connected by a spring. An external hit gives a velocity of 21 m/s to the heavier block towards the lighter one. Velocities of both blocks (heavier and lighter one) in the centre of mass frame, just after the kick will be respectively:
(Consider direction of motion of heavier block as +ve direction)
(Consider direction of motion of heavier block as +ve direction)
- 6 m/s, 10 m/s
- 6 m/s, −15 m/s
- 15 m/s, 15 m/s
- 3 m/s, 5 m/s
Q. For the arrangement shown in the figure, m1=6 kg and m2=4 kg. If the string is light and inextensible and the pulley and surfaces are frictionless, find the magnitude of the acceleration of the center of mass.
(Take g=10 m/s2)
(Take g=10 m/s2)
- 4 m/s2
- 10 m/s2
- 6 m/s2
- 2.88 m/s2
Q. For a spring block system as shown in figure, a time varying force F=5t N is applied on mass 2 kg. After 10 seconds, velocity of 3 kg mass is 30 m/s. Find the velocity of 2 kg mass at this instant.
- 40 m/s
- 80 m/s
- 803 m/s
- 20 m/s
Q. A body of mass 10 kg moving with velocity of 10 m/s hits another body of mass 30 kg moving with velocity 3 m/s in same direction. The co-efficient of restitution is 14. The velocity of centre of mass after collision will be
- 20 m/s
- 40 m/s
- 194m/s
- 234m/s
Q. For a spring block system as shown in figure, a time varying force F=5t N is applied on mass 2 kg. After 10 seconds, velocity of 3 kg mass is 30 m/s. Find the velocity of 2 kg mass at this instant.
- 40 m/s
- 80 m/s
- 803 m/s
- 20 m/s
Q. A man of mass 75 kg is standing on a platform of mass 15 kg kept on a smooth horizontal surface. The man starts moving on the platform with a velocity of 20 m/s relative to the platform. Then, magnitude of the recoil velocity of the platform is
- 12.33 m/s
- 20 m/s
- 25 m/s
- 16.66 m/s
Q. Two blocks of masses 5 kg and 2 kg are placed at rest on a frictionless surface and connected by a spring. An external hit gives a velocity of 21 m/s to the heavier block towards the lighter one. Velocities of both blocks (heavier and lighter one) in the centre of mass frame, just after the kick will be respectively:
(Consider direction of motion of heavier block as +ve direction)
(Consider direction of motion of heavier block as +ve direction)
- 6 m/s, 10 m/s
- 6 m/s, −15 m/s
- 15 m/s, 15 m/s
- 3 m/s, 5 m/s
Q. In the figure shown below, mA=2 kg and mB=3 kg. A force F=40 N is applied on 2 kg block as shown. Find the acceleration of COM of the system. (Neglect friction everywhere and assume the string to be inextensible)
- 1.2 m/s2
- 1 m/s2
- 2.4 m/s2
- 2 m/s2
Q. Two blocks are attached to the pulley as shown in the arrangement.
If the string is inextensible and all surfaces are frictionless, find out the magnitude acceleration of COM of the system. (Take g=10 m/s2)
If the string is inextensible and all surfaces are frictionless, find out the magnitude acceleration of COM of the system. (Take g=10 m/s2)
- 1.6 m/s2
- 0.4 m/s2
- 0.16 m/s2
- 4 m/s2
Q. A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x)= bx−2n, where b and n are constants and x is the position of the particle. The acceleration of the particle as a function of x, is given by
Q. A particle of mass m is moving with a constant acceleration 2a towards another particle of mass 4m as shown in figure. Mass 4m is also moving with acceleration a towards the particle of mass m. Find the acceleration of COM of the system.
- a/5 (towards left)
- 2a/5 (towards left)
- a/5 (towards right)
- 2a/5 (towards right)
Q. A man wearing a bullet-proof vest stands still on roller skates. The total mass is 80 kg. A bullet of mass 20 grams is fired at 400 m/s. It is stopped by the vest and man falls to the ground. What is then, the velocity of man ?
- 1 m/s
- 0.1 m/s
- 2 m/s
- 2.5 m/s
Q. A pulley mass arrangement is shown is the figure. A force of 50 N is applied on the 2 kg block. Find the acceleration of COM of the system.
- 1.6 m/s2
- 2 m/s2
- 10 m/s2
- 0 m/s2
Q. A man wearing a bullet-proof vest stands still on roller skates. The total mass is 80 kg. A bullet of mass 20 grams is fired at 400 m/s. It is stopped by the vest and man falls to the ground. What is then, the velocity of man ?
- 1 m/s
- 2 m/s
- 2.5 m/s
- 0.1 m/s