Second Law of Motion
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A rope which can withstand a maximum tension of 400 N is hanging from a tree. If a monkey of mass 30 kg climbs up the rope, in which of the following cases will the rope break? Take g=10ms−2 and neglect the mass of the rope.
The monkey climbs up with a uniform speed of 5 ms−1.
The monkey climbs up with a uniform acceleration of 2 ms−2.
The monkey climbs up with a uniform acceleration of 5 ms−2.
The monkey climbs down with a uniform acceleration of 5 ms−2.
(Take g=10 m/s2)
- 20:3
- 5:1
- 3:1
- 5:2
- √5Sv2ρ
- √2Sv2ρ
- √7Sv2ρ
- √3Sv2ρ
- 10, 10
- 15, 5
- 35, −15
- 25, −5
- 140 N
- 100 N
- 60 N
- 30 N
- tan−152
- tan−114
- tan−112
- tan−132
Force exerted on wall is
- 2 aV2dcosθ
- 2 aV2dsinθ
- 2 aVdcosθ
- aVd cosθ
- m2Fm1+m2
- m1Fm1+m2
- m1F
- m2F
- √2pk
- 2√pk
- 2√2pk
- 2√kp
Two masses m and 2m are joined to each other by means of a frictionless pulley as shown below. When the mass 2m is released, the mass m will ascend with an acceleration of
g3
g2
g
2g
A force F is applied horizontally to a block A of mass m1 which is in contact with a block B of mass m2, as shown in the figure. If the surfaces are frictionless, the force exerted by A on B is equal to
m1Fm2
m2Fm1
m1Fm1+m2
m2Fm1+m2
Column-IColumn-II(a) 1 kg block(p) will remain stationary(b) 2 kg block(q) will move down(c) 3 kg block(r) will move up(a) 4 kg block(s) 5 m/s2(t) 10 m/s2
- a−t, b−p, c−s, d−q
- a−p, b−t, c−s, d−q
- a−r, t, b−p, c−q, d−q, s
- a−r, b−p, c−q, d−p
- Possible value of x is only x=2 m
- Possible value of x is not only x=2 m, but there exists some other value of x also
- Time taken is 2 s
- All of the above
A mass m is suspended from a rigid support P by means of a massless string as shown in the figure. A horizontal force F is applied at point O of the rope. The system is in equilibrium when the string makes an angle θ with the vertical. Then the relation between tension T, force F and angle θ is
F=T sin θ
F=T cos θ
F=Tsinθ
F=Tcosθ
On forgetting his 25th anniversary, Vijay as a present from his wife, receives a shoe of 0.5 kg thrown at him with 10 m/s velocity. Find the momentum of assault.
10 Kg m/s
5 N
0.5 N
5 kg m/s
- 5 m/s2
- 10 m/s2
- 25 m/s2
- 2.5 m/s2
- 300 N
- 30 N
- 150 N
- 3 N
नीचे दिए गए प्रश्न के लिए अनुच्छेद
A disc (M, R) rolling without slippage on a rough horizontal surface with coefficient of friction μ collides with smooth wall elastically.
किसी खुरदरे क्षैतिज पृष्ठ जिसका घर्षण गुणांक μ है, पर बिना फिसले लुढ़क रही एक डिस्क (M, R) चिकनी दीवार से प्रत्यास्थ रूप से टकराती है।
Q. Velocity of top-most point of disc just after collision, is
प्रश्न - टक्कर के ठीक बाद डिस्क के शीर्षतम बिन्दु का वेग है
- Zero
शून्य - 2v0
- v02
- v0
Two blocks of mass 2 kg and 4 kg are kept in contact with each other on a smooth horizontal surface. A horizontal force of 12 N is applied on the first block due to which they move with certain constant acceleration. Calculate the force between the blocks.
2 N
4 N
8 N
16 N
If the force on a rocket moving with a velocity of 300 m/s is 210 N, then the rate of combustion of the fuel is
0.7 kg/s
1.4 kg/s
0.07 kg/s
10.7 kg/s
A man of mass M is standing on a plank kept in a box. The plank and box as a whole has mass m. A light string passing over a fixed smooth pulley connects the man and box. If the box remains stationary, find the tension in the string and the force exerted by the man on the plank.
(m+M)g2, (M−m)g2
(m+M)g, (M−m)g2
(m+M)g2, (M−m)g
(m+M)g, (M−m)g
- 8.50 N s, 9.25 ms−1
- 4.25 N s, 9.25 ms−1
- 4.25 N s, 4.25 ms−1
- 8.50 N s, 4.25 ms−1
A block of mass M is pulled along a horizontal frictionless suface by a rope of mass m. If a force F is applied at the free end of the rope, the net force exerted on the block will be
FM(M+m)
Fm(M+m)
FM(M−m)
F
नीचे दिए गए प्रश्न के लिए अनुच्छेद
A disc (M, R) rolling without slippage on a rough horizontal surface with coefficient of friction μ collides with smooth wall elastically.
किसी खुरदरे क्षैतिज पृष्ठ जिसका घर्षण गुणांक μ है, पर बिना फिसले लुढ़क रही एक डिस्क (M, R) चिकनी दीवार से प्रत्यास्थ रूप से टकराती है।
Q. Just after the collision, velocity of point of disc in contact with floor, is
प्रश्न - टक्कर के ठीक बाद, डिस्क के उस बिन्दु, जो फर्श के साथ सम्पर्क में है, का वेग है
- v02
- 3v02
- 2v0
- 5v02