Uniform Circular Motion
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- Gravitational pull
- Speed of rotation
- Surface tension
- Tension in a spring
एक कण किसी सरल रेखा के अनुदिश इस प्रकार गति करता है कि किसी समय (t) पर इसके वेग (v) को v = (2t – 1) m/s द्वारा व्यक्त किया जाता है, जहाँ t सेकण्ड में है। प्रथम सेकण्ड में कण द्वारा तय की गई कुल दूरी है
- 38 m
- 12 m
- 14 m
- Zero
(शून्य)
- r2r1
- r1r2
- 1
- None of these
The relation between ′h′ and ′ω′ is
- h=ω2g
- h=R2
- h=R−gω2
- None
A car moves on a circular path of radius 10 metre. It complete 5 revolution in 5 minute. What is its average speed?
10 π m / minute
20 π m / minute
30 π m / minute
5 π m / minute
एक कण प्रारम्भ में विराम में है, यह x-अक्ष के अनुदिश इस प्रकार गति करता है कि इसका त्वरण, समय t के साथ a = (4t + 5) m/s2 के अनुसार परिवर्तित हो। यदि यह मूल बिन्दु से गति प्रारम्भ करता है, तब 2 सेकण्ड में कण द्वारा तय की गई दूरी होगी
- 234m
- 493m
- 463m
- 517m
A motor cyclist going round in a circular track at constant speed has
Constant linear velocity
Constant acceleration
Constant angular velocity
Constant force
An object is moving in a circle of radius 100 m with a constant speed of 31.4 m/s. What is its average speed for one complete revolution
Zero
31.4 m/s
3.14 m/s
√2×31.4 m/s
- a constant velocity.
- a constant acceleration
- an acceleration of constant magnitude.
- an acceleration which varies with time in magnitude.
A particle is moving along a circular path of radius with tangential acceleration of The particle is initially at rest.
Based on above information, answer the following question:
3.The distance travelled by the particle in is
- positive
- negative
- zero
- either positive or zero
The average acceleration vector for a particle having a uniform circular motion is
A constant vector of magnitude v2r
A vector of magnitude v2rdirected normal to the plane of the given uniform circular motion
Equal to the instantaneous acceleration vector at the start of the motion
A null vector
- 3 : 5 : 7
- 3 : 4 : 5
- 7 : 11 : 6
- 3 : 5 : 6
- 1
- 2
- 3
- 5
- x=−1.5
- x=3
- Magnetic field is along z - direction.
- Kinetic energy of the particle is constant
- 360∘
- 180∘
- 45∘
- 0∘
- 5π6 rad/s
- 3π2 rad/s
- π3 rad/s
- π2rad/s
किसी समय t पर एक कण के निर्देशांकों को x = 4t – 3t2 तथा y = 3t द्वारा व्यक्त किया जाता है। कण द्वारा अनुसरित प्रक्षेप-पथ की समीकरण है
- 3x = 4y – 3y2
- 3x = y – 4y2
- 3x = 4y – y2
- x = 3y – 4y2
- Velocity
- Acceleration
- Kinetic energy
- Displacement
- 0.25 cm
- 2 cm
- 4 cm
- 2.5 cm
- 1.732v m/s
- 1.414v m/s
- 0.707v m/s
- v m/s
- 0
- 10√3 m/s
- 10 m/s
- 10√2 m/s
- 167π rads2
- −167π rads2
- 8π7 rads2
- −8π7 rads2
Assume that the earth goes round the sun in a circular orbit with a constant speed of 30 km/s. Then,
The average velocity of the earth from 1st Jan, 90 to 30th June, 90 is zero
- The average acceleration during the above period is 60 km/s2
The average speed from 1st Jan, 90 to 31st Dec, 90 is zero
The instantaneous acceleration of the earth points towards the sun.
A particle is moving in a circle with uniform speed v. In moving from a point to another diametrically opposite point
The momentum changes by mv
The momentum changes by 2mv
The kinetic energy changes by (12)mv2
The kinetic energy changes by mv2
- 12
- 18
- 24
- 54
- 3 : 5 : 7
- 3 : 4 : 5
- 7 : 11 : 6
- 3 : 5 : 6
- circular clockwise
- circular anti-clockwise
- elliptical
- rectilinear
- 10√2 m/s
- 10 m/s
- 10√3 m/s
- Zero
- 8%
- 0.08%
- 0.008%
- 0.0008%