A $1.5 m$ wide by $2.5 m$ long water bed weighs $1025 N$ . Find the pressure that the water bed exerts on the floor. Assume that the entire lower surface of the bed makes contact with the floor.

273.3 P a

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373.5 P a

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173.3 P a

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473.3 P a

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Solution

The correct option is A $273.3 P a$
Pressure exerted by water bed will be force applied per unit area.
$P = \frac{F}{A}$
Given:
Force= $1025 N$
Area= $1.5 m \times 2.5 m = 3.75 m^{2}$

Pressure
$= \frac{1025 N}{3.75 m^{2}} = 273.3 N / m^{2} = 273.3 P a$

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A 1.5m wide by 2.5m long water bed weighs 1025N. Find the pressure that the water bed exerts on the floor. Assume that the entire lower surface of the bed makes contact with the floor.

The correct option is A 273.3PaPressure exerted by water bed will be force applied per unit area.P=FAGiven:Force= 1025 NArea= 1.5m×2.5m=3.75m2Pressure =1025 N3.75 m2=273.3 N/m2=273.3 Pa

A $1.5 m$ wide by $2.5 m$ long water bed weighs $1025 N$ . Find the pressure that the water bed exerts on the floor. Assume that the entire lower surface of the bed makes contact with the floor.

The correct option is A $273.3 P a$
Pressure exerted by water bed will be force applied per unit area.
$P = \frac{F}{A}$
Given:
Force= $1025 N$
Area= $1.5 m \times 2.5 m = 3.75 m^{2}$

Pressure
$= \frac{1025 N}{3.75 m^{2}} = 273.3 N / m^{2} = 273.3 P a$