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Standard XII

Physics

Friction and Vertical Circular Motion Problems

A 1 kg ston...

Question

A $1 k g$ stone at the end of $1 m$ long string is whirled in a vertical circle at a constant speed of $4 m s^{- 1}$ . The tension in the string is 6 N when the stone is

At the top of the circle

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At the bottom of the circle

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Half way down

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None of above

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Solution

The correct option is D At the top of the circle
At top $T = \frac{m v^{2}}{R} - m g$
$= \frac{16}{1} - 10$
$= 6 N .$
Hence, the answer is at the top of the circle.

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A 1 kg stone at the end of 1 m long string is whirled in a vertical circle at a constant speed of 4 ms−1. The tension in the string is 6 N when the stone is

The correct option is D At the top of the circleAt top T=mv2R−mg =161−10 =6N.Hence, the answer is at the top of the circle.

A $1 k g$ stone at the end of $1 m$ long string is whirled in a vertical circle at a constant speed of $4 m s^{- 1}$ . The tension in the string is 6 N when the stone is

The correct option is D At the top of the circle
At top $T = \frac{m v^{2}}{R} - m g$
$= \frac{16}{1} - 10$
$= 6 N .$
Hence, the answer is at the top of the circle.