A $1000 - k g$ car traveling north at $15 m / s$ collides with a $2000 - k g$ truck travelling east at $10 m / s$ . The occupants, wearing seat belts, are uninjured, but the two vehicles move away from the impact point as one. The insurance adjustor asks you to find the velocity of the wreckage just after impact.

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Solution

From conservation of momentum

Initial momentum = final momentum

$m \to u + M \to U = (m + M) \to V$

$1000 \times 15^i + 2000 \times 10^j = (1000 + 2000) \to V$

$\to V = 5^i + 10^j$

Final velocity when they stick together is $5^i + 10^j$

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A 1000−kg car traveling north at 15m/s collides with a 2000−kg truck travelling east at 10m/s. The occupants, wearing seat belts, are uninjured, but the two vehicles move away from the impact point as one. The insurance adjustor asks you to find the velocity of the wreckage just after impact.

From conservation of momentum Initial momentum = final momentum m→u+M→U=(m+M)→V 1000×15^i+2000×10^j=(1000+2000)→V →V=5^i+10^j Final velocity when they stick together is 5^i+10^j

From conservation of momentum

Initial momentum = final momentum

$m \to u + M \to U = (m + M) \to V$

$1000 \times 15^i + 2000 \times 10^j = (1000 + 2000) \to V$

$\to V = 5^i + 10^j$

Final velocity when they stick together is $5^i + 10^j$