A 16 gm mass is moving in the +x direction at 30 cm/s while a 4 gm is moving in the -x direction at 50 cm/s. They collide head - on and stick together. Their common velocity after impact is

0.14 c m / s

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0.14 m / s

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0 m s^{- 1}

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0.3 m / s

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Solution

The correct option is B $0.14 m / s$
Using conservation of linear momentum
$m_{1} u_{1} + m_{2} u_{2} = m v$
$16 \times 30 - 4 \times 50 = 20 \times v$
$480 - 200 = 20 v$
$v = 0.14 m / s$

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A 16 gm mass is moving in the +x direction at 30 cm/s while a 4 gm is moving in the -x direction at 50 cm/s. They collide head - on and stick together. Their common velocity after impact is

The correct option is B 0.14m/sUsing conservation of linear momentumm1u1+m2u2=mv16×30−4×50=20×v480−200=20vv=0.14m/s

The correct option is B $0.14 m / s$
Using conservation of linear momentum
$m_{1} u_{1} + m_{2} u_{2} = m v$
$16 \times 30 - 4 \times 50 = 20 \times v$
$480 - 200 = 20 v$
$v = 0.14 m / s$