A 2 kg mass moving with a velocity of $10 m s^{- 1}$ collides with another 6 kg mass moving in opposite direction with a velocity of $20 m s^{- 1}$ . After the collision, they stick and move together. Their common velocity is m/s and the momentum is kg m/s.

12.5

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7.5

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100

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Solution

The correct option is D 100
$m_{1} u_{1} + m_{2} u_{2} = (m_{1} + m_{2}) v (2) (10) - (6) (20) = (8) v \Rightarrow v = \frac{100}{8} m / s = 12.5 m / s p = 8 v = 100 k g m / s$

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A 2 kg mass moving with a velocity of 10 ms−1 collides with another 6 kg mass moving in opposite direction with a velocity of 20 ms−1. After the collision, they stick and move together. Their common velocity is m/s and the momentum is kg m/s.

The correct option is D 100m1u1+m2u2=(m1+m2)v(2)(10)−(6)(20)=(8)v⇒v=1008m/s=12.5 m/sp=8v=100 kgm/s

A 2 kg mass moving with a velocity of $10 m s^{- 1}$ collides with another 6 kg mass moving in opposite direction with a velocity of $20 m s^{- 1}$ . After the collision, they stick and move together. Their common velocity is m/s and the momentum is kg m/s.

The correct option is D 100
$m_{1} u_{1} + m_{2} u_{2} = (m_{1} + m_{2}) v (2) (10) - (6) (20) = (8) v \Rightarrow v = \frac{100}{8} m / s = 12.5 m / s p = 8 v = 100 k g m / s$