A 2 kg mass moving with a velocity of $10 m s^{- 1}$ collides with another 6 kg mass moving in opposite direction with a velocity of $20 m s^{- 1}$ . After the collision, they stick and move together. Their common velocity is m/s and the momentum is kg m/s.

12.5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

7.5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

100

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct options are
A 12.5
D 100
$m_{1} u_{1} + m_{2} u_{2} = (m_{1} + m_{2}) v (2) (10) - (6) (20) = (8) v \Rightarrow v = \frac{100}{8} m / s = 12.5 m / s p = 8 v = 100 k g m / s$

Suggest Corrections

Similar questions

Q. A 2 kg mass moving with a velocity of

10 m s^{- 1}

collides with another 6 kg mass moving in opposite direction with a velocity of

20 m s^{- 1}

. After the collision, they stick and move together. Their common velocity is m/s and the momentum is kg m/s.

A 2 kg mass moving with a velocity of $10 m s^{- 1}$ collides with another 6 kg mass moving in opposite direction with a velocity of $20 m s^{- 1}$ . After the collision, they stick and move together. Find their common velocity and the momentum.

Q. A

6 k g

mass moving with a velocity of

20 m s^{- 1}

collides with another

2 k g

mass moving in opposite direction with a velocity of

10 m s^{- 1}

. The momentum of system is.

Q. A railway truck of mass

2 \times 10^{4} k g

, travelling at

0.5 m s^{- 1}

collides with another of half of it's mass moving in opposite direction with a velocity of

0.4 m s^{- 1}

. If they stick together after the collision then their common velocity is:

Q. A body of mass 2 kg moving with a velocity of 3ms

^{- 1}

collides head on with a body of mass 1 kg moving with a velocity of 4 ms

^{- 1}

in opposite direction. After collision the two bodies stick together and move with a common velocity.

Join BYJU'S Learning Program

A 2 kg mass moving with a velocity of 10 ms−1 collides with another 6 kg mass moving in opposite direction with a velocity of 20 ms−1. After the collision, they stick and move together. Their common velocity is m/s and the momentum is kg m/s.

The correct options are A 12.5 D 100m1u1+m2u2=(m1+m2)v(2)(10)−(6)(20)=(8)v⇒v=1008m/s=12.5 m/sp=8v=100 kgm/s

A 2 kg mass moving with a velocity of $10 m s^{- 1}$ collides with another 6 kg mass moving in opposite direction with a velocity of $20 m s^{- 1}$ . After the collision, they stick and move together. Their common velocity is m/s and the momentum is kg m/s.

The correct options are
A 12.5
D 100
$m_{1} u_{1} + m_{2} u_{2} = (m_{1} + m_{2}) v (2) (10) - (6) (20) = (8) v \Rightarrow v = \frac{100}{8} m / s = 12.5 m / s p = 8 v = 100 k g m / s$