A $2 k g$ object is moving at $3 m / s$ . A $4 N$ force is applied in the direction of motion and then removed after the object has travelled an additional $5 m$ . The work done by this force is:

10 J

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15 J

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20 J

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25 J

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Solution

The correct option is C $20 J$
intial velocity $u = 3 m / s$
final velocity $v^{2} = u^{2} + 2 a s = 3^{2} + (2 \times 2 \times 5) = 29$ $⟹ v = 5.3 m / s$

$K E = \frac{1}{2} m (v^{2} - u^{2}) = \frac{1}{2} \times 2 \times ((5.3)^{2} - 3^{2}) = 20 J$

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Q. An object of

40 k g

mass is moving with velocity

2 m / s

. A force applied on it increases its velocity to

5 m / s

. Find the work done by force.

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A 2kg object is moving at 3m/s. A 4N force is applied in the direction of motion and then removed after the object has travelled an additional 5m. The work done by this force is:

The correct option is C 20Jintial velocity u=3m/sfinal velocity v2=u2+2as=32+(2×2×5)=29 ⟹v=5.3m/sKE=12m(v2−u2)=12×2×((5.3)2−32)=20J

A $2 k g$ object is moving at $3 m / s$ . A $4 N$ force is applied in the direction of motion and then removed after the object has travelled an additional $5 m$ . The work done by this force is:

The correct option is C $20 J$
intial velocity $u = 3 m / s$
final velocity $v^{2} = u^{2} + 2 a s = 3^{2} + (2 \times 2 \times 5) = 29$ $⟹ v = 5.3 m / s$

$K E = \frac{1}{2} m (v^{2} - u^{2}) = \frac{1}{2} \times 2 \times ((5.3)^{2} - 3^{2}) = 20 J$