A 2m long conductor, carries a current of 50 A at a magnetic field of $10^{- 1} T$ . The force on the conductor is:

10 N

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100 N

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1000 N

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10,000 N

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Solution

The correct option is A 10 N
Force on a current carrying conductor of length $l$ placed in magnetic field is given by

$F = B I l$

$= 10^{- 1} T \times 50 A \times 2 m$

$= 10 N$

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A 2m long conductor, carries a current of 50 A at a magnetic field of 10−1T. The force on the conductor is:

The correct option is A 10 NForce on a current carrying conductor of length l placed in magnetic field is given by F=BIl=10−1T×50A×2m=10N

A 2m long conductor, carries a current of 50 A at a magnetic field of $10^{- 1} T$ . The force on the conductor is:

The correct option is A 10 N
Force on a current carrying conductor of length $l$ placed in magnetic field is given by

$F = B I l$

$= 10^{- 1} T \times 50 A \times 2 m$

$= 10 N$