A 4 kg mass is resting on a horizontal surface- for this surface - 8- 0-6 and - k- 0-2- force required to move the body with 5ms -2 acceleration is g-10ms -2

The correct option is C 25 N [ F_max #160; #160;=( 6 10 #160; ) 40; =2μ N; ...

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Standard VII

Physics

Weight and Mass

A 4 kg mass i...

Question

A 4 kg mass is resting on a horizontal surface. for this surface $μ_{8}$ = 0.6 and $μ_{k}$ = 0.2. force required to move the body with ${5 m s}^{- 2}$ acceleration is $({g = 10 m s}^{- 2})$

20 N

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24 N

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25 N

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32 N

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Solution

The correct option is C 25 N
$\begin{matrix} F_{max} = (\frac{6}{10}) 40 = 2 μ N = 5 m / s^{2} \Rightarrow F - f_{k} = m (5) \Rightarrow F - \frac{2}{10} \times 40 = 20 F = 25 N \end{matrix}$
$∴$ Option $C$ is correct .

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A 4 kg mass is resting on a horizontal surface. for this surface μ8= 0.6 and μk= 0.2. force required to move the body with 5ms−2 acceleration is (g=10ms−2)

The correct option is C 25 NFmax=(610)40=2μN=5m/s2⇒F−fk=m(5)⇒F−210×40=20F=25N∴ Option C is correct .

A 4 kg mass is resting on a horizontal surface. for this surface $μ_{8}$ = 0.6 and $μ_{k}$ = 0.2. force required to move the body with ${5 m s}^{- 2}$ acceleration is $({g = 10 m s}^{- 2})$

The correct option is C 25 N
$\begin{matrix} F_{max} = (\frac{6}{10}) 40 = 2 μ N = 5 m / s^{2} \Rightarrow F - f_{k} = m (5) \Rightarrow F - \frac{2}{10} \times 40 = 20 F = 25 N \end{matrix}$
$∴$ Option $C$ is correct .