A 50 Hz AC current of crest value 1 A flows through the primary of a transformer. If the mutual inductance between the primary and the secondary be 0.5 H, find the crest voltage induced in the secondary.

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Solution

The emf induced in the secondary is given by $E = M \frac{d i}{d t} = 0.5 \times \frac{1 - (- 1)}{\frac{1}{100}} = 0.5 \times 200 = 100 V$

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A 50 Hz AC current of crest value 1 A flows through the primary of a transformer. If the mutual inductance between the primary and the secondary be 0.5 H, find the crest voltage induced in the secondary.

The emf induced in the secondary is given by E=Mdidt=0.5×1−(−1)1100=0.5×200=100 V

The emf induced in the secondary is given by $E = M \frac{d i}{d t} = 0.5 \times \frac{1 - (- 1)}{\frac{1}{100}} = 0.5 \times 200 = 100 V$