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Question

A 5V battery with internal resistance 2Ω and a 2V battery with internal resistance 1Ω are connected to a 10Ω resistor as shown in figure.

The current in the 10Ω resistor is


A

0.27A, P2 to P1

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B

0.03A, P1 to P2

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C

0.03A, P2 to P1

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D

0.27A, P1 to P2

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Solution

The correct option is C

0.03A, P2 to P1


Current throught 10Ω resister
=l1l2
=132A Loop(1)
=0.03A from P2 to P1 12l110l2=5 ---------(1)
Loop(2)
10l1+11l2=2 ----------------(2)
Solving (1) & (2)
l2=75/32A
I1=74.5/32A


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