A 6 kg mass travelling at $2.5$ ms $^{- 1}$ collides head on with a stationary 4 kg mass. After the collision the 6 kg mass travels in its original direction with a speed of $1$ ms $^{- 1}$ . The final velocity of 4 kg mass

1

^{- 1}

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2.25

^{- 1}

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2

^{- 1}

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0

^{- 1}

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Solution

The correct option is B $2.25$ ms $^{- 1}$
Use momentum conservation,
$m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}$
But $m_{1} = 6$ kg $, m_{2} = 4$ kg, $u_{1} = 2.5$ ms $^{- 1}, u_{2} = 0$ ms $^{- 1}, v_{1} = 1$ ms $^{- 1}, v_{2} = ?$
$\Rightarrow 6 \times 2.5 + 4 \times (0) = 6 \times 1 + 4 \times v_{2}$
$\Rightarrow 9 = 4 v \Rightarrow v = 2.25$ ms $^{- 1}$ .

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