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Byju's Answer

Standard XII

Physics

V-t to a-t Graph

460 Hz excite...

Question

A 60 $H z$ exciter sets string into a mode as shown in figure. Length of string is 45 $c m$ . If displacement amplitudes of particles at $x = 7.5$ , $x = 18$ & $x = 27$ are $A_{1}, A_{2} & A_{3}$ , then

A_{3} > A_{2} > A_{1}

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A_{1} > A_{2} > A_{3}

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A_{1} > A_{2} = A_{3}

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A_{1} = A_{2} > A_{3}

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Solution

The correct option is C $A_{1} > A_{2} = A_{3}$
$A_{1} > A_{2} = A_{3}$ $(A_{2} & A_{3}$ are same due to symmetry)

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A 60 Hz exciter sets string into a mode as shown in figure. Length of string is 45 cm. If displacement amplitudes of particles at x=7.5, x=18 & x=27 are A1,A2 & A3, then

The correct option is C A1>A2=A3A1>A2=A3 (A2 & A3 are same due to symmetry)

A 60 $H z$ exciter sets string into a mode as shown in figure. Length of string is 45 $c m$ . If displacement amplitudes of particles at $x = 7.5$ , $x = 18$ & $x = 27$ are $A_{1}, A_{2} & A_{3}$ , then

The correct option is C $A_{1} > A_{2} = A_{3}$
$A_{1} > A_{2} = A_{3}$ $(A_{2} & A_{3}$ are same due to symmetry)