The correct option is A a^2+2ab+b^2 nbsp;(a+b)^2 = (a+b)(a+b) nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; = a(a+b)+b(a+b) nbsp ...

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Byju's Answer

Standard VI

Mathematics

Algebraic Identities

a+b2=

Question

$(a + b)^{2}$ = _____.

a^{2} + 2 a b + b^{2}

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a^{2} - 2 a b + b^{2}

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a^{2} + 2 a b - b^{2}

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a^{2} - 2 a b - b^{2}

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Solution

The correct option is A $a^{2} + 2 a b + b^{2}$
$(a + b)^{2} = (a + b) (a + b)$
$= a (a + b) + b (a + b)$
$= a^{2} + a b + b a + b^{2}$
$= a^{2} + 2 a b + b^{2}$

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Similar questions

Q. The correct order of stability for the following species is:

B_{2}, B_{2}^{-} a n d B_{2}^{+}

Q. Prove the followings,

(a + b)^{2} + (a - b)^{2} = 2 (a^{2} + b^{2})

ii)

(a + b)^{2} - (a - b)^{2} = 4 a b

Which of the following is correct?
a) $(a - b)^{2} = a^{2} + 2 a b - b^{2}$
b) $(a - b)^{2} = a^{2} - 2 a b + b^{2}$
c) $(a - b)^{2} = a^{2} - b^{2}$
d) $(a + b)^{2} = a^{2} + 2 a b - b^{2}$

Q. Simplify

\frac{a + \sqrt{a^{2} - b^{2}}}{a - \sqrt{a^{2} - b^{2}}} + \frac{a - \sqrt{a^{2} - b^{2}}}{a + \sqrt{a^{2} - b^{2}}}

Q. Factorise:

(a + b)^{2} - 2 (a^{2} - b^{2}) + (a - b)^{2}

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(a+b)2 = _____.

The correct option is A a2+2ab+b2 (a+b)2=(a+b)(a+b) =a(a+b)+b(a+b) =a2+ab+ba+b2 =a2+2ab+b2

$(a + b)^{2}$ = _____.

The correct option is A $a^{2} + 2 a b + b^{2}$
$(a + b)^{2} = (a + b) (a + b)$
$= a (a + b) + b (a + b)$
$= a^{2} + a b + b a + b^{2}$
$= a^{2} + 2 a b + b^{2}$