Question

A bag contains 3 blue and 7 red balls. Find the probability that a ball selected at random from the bag will be a blue ball

• A. $\frac{3}{7}$
• B. $\frac{7}{10}$
• C. $\frac{3}{10}$
• D. $\frac{4}{10}$

Answer 1

Answer: (C)

$\frac{3}{10}$

Total number of ball in the bag $=3+7=10$

So a ball can be selected from the bag in 10 ways Now there are 3 blue balls in the bag So a blue ball cab be selected from the bag in 3 ways Hence the required probability $=3/10$