A ball hits a wall with a velocity of $30$ $m / s$ and re bounces with same velocity. What is change in its velocity.

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Solution

Initial velocity $\to u = - 30^n$ where $^n$ is unit vector normal to surface which ball strikes.

And final velocity is $\to v = 30^n$ .

Hence, $Δ \to v = 60^n$

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A ball hits a wall with a velocity of 30 m/s and re bounces with same velocity. What is change in its velocity.

Initial velocity →u=−30^n where ^n is unit vector normal to surface which ball strikes.And final velocity is →v=30^n.Hence, Δ→v=60^n

A ball hits a wall with a velocity of $30$ $m / s$ and re bounces with same velocity. What is change in its velocity.

Initial velocity $\to u = - 30^n$ where $^n$ is unit vector normal to surface which ball strikes.

And final velocity is $\to v = 30^n$ .

Hence, $Δ \to v = 60^n$