A ball is rolled off the edge of a horizontal table at a speed of 4 m/s. It hits the ground after 0.4 second. Which statement given below is true(Take g=10m/s2)
Vertical component of velocity of ball at point P
vv = 0 + gt = 10 × 0.4 = 4 m/s
Horizontal component of velocity = inital velocity
⇒ vH = 4 m/s
So the speed with which it hits the ground
v = √(vH2+vy2) = 4√2 m/s
and tan θ = vVvH =44 = 1 ⇒ θ = 45∘
It means the ball hits the ground at an angle of 45∘ to the horizontal.
Height of the table h = 12 g t2 = 12 × 10 × (0.4)2 = 0.8m
Horizontal distance travelled by the ball from the edge of table h = ut = 4 × 0.4 = 1.6m