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Question

A ball is thrown upward with an initial velocity of 100 ms1. Find the height of the ball after 15 s. Take g=10 ms2

A
375 m
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B
425 m
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C
395 m
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D
275 m
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Solution

The correct option is A 375 m
Here, u=100 ms1, a=g=10 ms2
At highest point, v=0
As v=u+gt0=10010×t
Time taken to reach highest point,
t=10010=10 s
The ball will return to the ground at t=20 s
Corresponding velocity - time graph of the ball is shown in
Height attained after 15 s=Area of ΔAOB+Area of ΔBCD
=500+12(1510)×(50)=500125=375 m

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