A ball moving with a momentum of $5 k g {m s}^{- 1}$ strikes against a wall at an angle of $45^{o}$ and is reflected at the same angle. Calculate the change in momentum.

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Solution

Since the initial momentum and final momentum is differ by $90^{0}$
Change in momentum $(Δ p) = \sqrt{p_{1}^{2} + p_{2}^{2}}$
$\Rightarrow Δ p = \sqrt{2} p$
$\Rightarrow Δ p = 5 \sqrt{2} k g m s^{- 1}$

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A ball moving with a momentum of 5 kg ms−1 strikes against a wall at an angle of 45o and is reflected at the same angle. Calculate the change in momentum.

Since the initial momentum and final momentum is differ by 900Change in momentum (Δp)=√p21+p22⇒Δp=√2p⇒Δp=5√2kgms−1

A ball moving with a momentum of $5 k g {m s}^{- 1}$ strikes against a wall at an angle of $45^{o}$ and is reflected at the same angle. Calculate the change in momentum.

Since the initial momentum and final momentum is differ by $90^{0}$
Change in momentum $(Δ p) = \sqrt{p_{1}^{2} + p_{2}^{2}}$
$\Rightarrow Δ p = \sqrt{2} p$
$\Rightarrow Δ p = 5 \sqrt{2} k g m s^{- 1}$