A ball of mass 0.4 kg moving with uniform speed of $2 m s^{- 1}$ strikes normally a wall and rebounds. Assuming the collision to be elastic and the time of contact of the ball with the wall as 0.4s, find the force exerted on the ball

1 N

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2 N

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3 N

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4 N

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Solution

The correct option is D
4 N

$F = \frac{Δ P}{Δ t} = \frac{[(0.4) (2)] - [(0.4) (- 2)]}{0.4} = 4 N$

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A ball of mass 0.4 kg moving with uniform speed of 2 ms−1 strikes normally a wall and rebounds. Assuming the collision to be elastic and the time of contact of the ball with the wall as 0.4s, find the force exerted on the ball

The correct option is D 4 N F=ΔPΔt=[(0.4)(2)]−[(0.4)(−2)]0.4=4N

A ball of mass 0.4 kg moving with uniform speed of $2 m s^{- 1}$ strikes normally a wall and rebounds. Assuming the collision to be elastic and the time of contact of the ball with the wall as 0.4s, find the force exerted on the ball

The correct option is D
4 N

$F = \frac{Δ P}{Δ t} = \frac{[(0.4) (2)] - [(0.4) (- 2)]}{0.4} = 4 N$