A ball of mass 1g carrying a charge 10−8C moves from a point A at potential 600V to a point B at zero potential. The change in its K.E. is :
A
−6×10−6erg
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B
−6×10−6J
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C
6×10−6J
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D
6×10−6erg
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Solution
The correct option is C6×10−6J As the work has been done by the field so it should be positive. The work done , W=q(VA−VB) We know that change in kinetic energy = work done =q(VA−VB)=10−8(600−0)=6×10−6J.