A ball of mass 1g and charge 10−8C moves from a point A having electric potential VA=600V to a point B, whose electric potential is zero. Velocity of the ball at point B is 20cm s−1. Velocity of the ball at point A is (Neglect gravitation)
A
16.7ms−1
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B
16.7cm s−1
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C
2.8ms−1
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D
2.8cm s−1
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Solution
The correct option is B16.7cm s−1 Work done by electric force for motion of charge from A to B :- (W)AB=ΔKE=qVAB 12mv2B−12mv2A=q(VA−VB) VB=0,VA=600 V12mv2A=12mv2B−qVA v2A=v2B−2qVAm After solving vA=16.7×10−2m/sec vA=16.7cm/sec