wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A ball of mass m moving with speed v strikes the vertical wall perpendicularly and bounce back with same speed. Collision is perfectly elastic. Calculate the magnitude of the change in momentum of the ball.

A
mv
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2mv
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
mv2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
mv4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
zero
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2mv
The ball bounces back with the same speed i.e v

u=v^i and v=v^i

Thus change in momentum ΔP=[mv(mv)]^i=2mv^i

|ΔP|=2mv

525456_485550_ans.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Second Law of Motion
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon