A ball released from a height Falls 5 metre in 1 second in 4 seconds its Falls through

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Solution

It does seem there is superfluous information here. Just knowing the ball falls 5 meters in one second is enough to compute the drop height after 4 seconds.

It's possible the key here is that the extra piece of information tells us that air drag can be neglected (otherwise the ball would have fallen less than 5 m in a second, given g=10m/s22

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