Question

A ball released from a height $h$, touches the ground in $t$ seconds. After $t/2$ seconds since dropping, the height of the body from the ground is :

• A. $\frac{h}{2}$
• B. $\frac{h}{4}$
• C. $\frac{3h}{4}$
• D. $\frac{3h}{2}$

Answer 1

Answer: (C)

$\frac{3h}{4}$

Let $h_1$ be the height from the body after release from the top position.

So, we know that, $S=\frac{g{t}^2}{2}$

So, for $t$ second of time, $h=\frac{g{t}^2}{2}$

And for $\frac{t}{2}$ second of time

$h_1=\frac{g(t/2{)}^2}{2}$

Taking ratio of $h$ and $h_1$,we find the distance travelled from top point.

$\frac{h}{h_1}=4$

$\Rightarrow h_1=\frac{h}{4}$

Now from bottom total height will be: $h-\frac{h}{4}=\frac{3h}{4}$