Question

A ballon contains $1500m^3$ of a helium at ${27}^o$C and $4$ atmospheric pressure. The volume of helium at $-3^o$C temperature and $2$ atmospheric pressure will be.

• A. $2700m^3$
• B. $1900m^3$
• C. $1700m^3$
• D. $1500m^3$

Answer 1

Answer: (A)

$2700m^3$

The general gas equation is $\frac{p_1{V}_1}{T_1}=\frac{p_2{V}_2}{T_2}=$gas constant
where $p_1.V_1,p_2.V_2$ are pressure and volume at temperatures $T_1$ and $T_2$ respectively.
Given $V_1=1500m^3,T_1=27+273=300$K,
$p_1=4$atm
$T_2=-3^o$C$=273-3=270$K, $p_2=2$atm.
$\therefore V_2=\frac{p_1{V}_1}{T_1}\times \frac{T_2}{p_2}$
$V_2=\frac{4\times 1500}{300}\times \frac{270}{2}$
$V_2=2700m^3$.