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Question

A bar magnet when placed at an angle of 30 to the direction of magnetic field induction of 5×102 T, experiences a moment of couple 25×106 Nm. If the length of the magnet is 5 cm its pole strength is

A
2×102 Am
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B
5×102 Am
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C
2 Am
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D
5 Am
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Solution

The correct option is A 2×102 Am
τ=MB sin θτ=(mL)B sin θ
25×106=(m×5×102)×5×102×sin 30
m=2×102 Am

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