MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

First Equation of Motion

A baseball is...

Question

A baseball is popped straight up into the air and has a hanging -time of 6 second .Determine the maximum height to which the ball rises?

Open in App

Solution

Time taken to reach the maximum height = 6/2 = 3 s

Final velocity, v = 0

Using first equation of motion, v = u + at

0 = u - 10 × 3

u = 30 m/s

Now,

s = ut + 1/2(at)^2

s= 30 × 3 – 12 × 10 × 3 × 3

Hence, s = 90 – 45 = 45 m

Suggest Corrections

thumbs-up

2

Similar questions

Q. A baseball is popped straight up into the air and has a hang-time of

6.25 s

. Determine the height to which the ball rises before it reaches its peak.

A baseball is popped straight up into the air and has a hang-time of 6 s. Determine the maximum height to which the ball rises.

Q. A baseball is popped straight up into the air and stays in air for 6 seconds before touching the ground. Determine the maximum height to which the ball rises? Use g = 10

m s^{- 2}

.

Q. A man throws balls into the air one after another. He always throws a ball when the previous one thrown has just reached the highest point. The height to which each ball rises, if he throws 5 balls per second is

(g = 10 m s^{- 2})

:

Q. A boy is throwing balls into the air one by one in such a way that when the first ball thrown reaches maximum height he starts to throw the second ball. He repeats this activity. To what height do the balls rise if he throws twice in a second?

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

First Equation of Motion

PHYSICS

Watch in App

explore_more_icon

Explore more

First Equation of Motion

Standard IX Physics

Join BYJU'S Learning Program

CrossIcon