Question

A battery has four cells in parallel, each has an e.m.f $1.5V$ and internal resistance $0.8\Omega$. The current delivered by it to a load of $2.8\Omega$ is

• A. 0.2A
• B. 0.4A
• C. 0.5A
• D. 0.6A

Answer 1

The correct option is C 0.5A

$E_{eff}=E=1.5V$
$r_{eff}=\frac{0.8}{4}=0.2V$
$\Rightarrow E_{eff}=I[R+r_{eff}]$
$1.5=I[2.8+0.2]$
$I=\frac{1.5}{3}=0.5A$