A battery has six cells in series and each cell has an electromagnetic force 1.5V and internal resistance 1Ω. If an external load of resistance 24Ω is connected to it. The potential drop across the load is
A
7.2V
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B
0.3V
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C
6.8V
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D
0.4V
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Solution
The correct option is A7.2V ⇒6E=I[24+6r] 6×1.530=I P.D across load = I x 24 =310×24 =3×125=7.2V