A black compound of manganese reacts with a halogen acid to give greenish-yellow gas. When an excess of this gas reacts with $N H_{3}$ an unstable trihalide is formed. In this process the oxidation state of nitrogen changes from :

-3 to+3

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-3 to 0

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-3 to+5

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0 to -3

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Solution

The correct option is D -3 to+3

A black color compound of manganese is $M n O_{2}$ reacted with halogen acid like $H C l$ ,it forms chlorine gas which in turn reacts with $N H_{3}$ to form $N C l_{3}$ where the oxidation state of N in $N H_{3}$ is changed form -3 to +3 in $N C l_{3}$
$M n O_{2} + 4 H C l \to M n C l_{2} + 2 H_{2} O + C l_{2}$ .

$N H_{3} + 3 C l_{2} = N C l_{3} + 3 H C l$ (-3 changes to +3).
Hence opton A is correct.

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A black compound of manganese reacts with a halogen acid to give greenish-yellow gas. When an excess of this gas reacts with NH3 an unstable trihalide is formed. In this process the oxidation state of nitrogen changes from :

A black compound of manganese reacts with a halogen acid to give greenish-yellow gas. When an excess of this gas reacts with $N H_{3}$ an unstable trihalide is formed. In this process the oxidation state of nitrogen changes from :