A block of mass 4 kg rests on a rough horizontal surface. If a horizontal force of 12 N is applied on the block, then the frictional force by the surface on the block is (μk=0.4,μs=0.5 and g=10 m/s2)
A
16 N
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B
12 N
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C
20 N
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D
8 N
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Solution
The correct option is B12 N Limiting static friction is given by flim=μsN =μsMg =0.5×4×10 =20 N flim>Fapplied
If applied force is less than limiting friction, then friction force will be equal to applied force. f=Fapplied f=12 N