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Byju's Answer

Standard XIII

Physics

Net Force

A block of ma...

Question

A block of mass $4 kg$ rests on a rough horizontal surface. If a horizontal force of $12 N$ is applied on the block, then the frictional force by the surface on the block is
$(μ_{k} = 0.4, μ_{s} = 0.5$ and $g = 10 {m/s}^{2})$

16 N

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20 N

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12 N

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8 N

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Solution

The correct option is C $12 N$
Limiting static friction is given by
$f_{l i m} = μ_{s} N$
$= μ_{s} M g$
$= 0.5 \times 4 \times 10$
$= 20 N$
$f_{l i m} > F_{applied}$
If applied force is less than limiting friction, then friction force will be equal to applied force.
$f = F_{applied}$
$f = 12 N$

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A block of mass 4 kg rests on a rough horizontal surface. If a horizontal force of 12 N is applied on the block, then the frictional force by the surface on the block is (μk=0.4,μs=0.5 and g=10 m/s2)

The correct option is C 12 NLimiting static friction is given by flim=μsN =μsMg =0.5×4×10 =20 N flim>Fapplied If applied force is less than limiting friction, then friction force will be equal to applied force. f=Fapplied f=12 N

A block of mass $4 kg$ rests on a rough horizontal surface. If a horizontal force of $12 N$ is applied on the block, then the frictional force by the surface on the block is
$(μ_{k} = 0.4, μ_{s} = 0.5$ and $g = 10 {m/s}^{2})$

The correct option is C $12 N$
Limiting static friction is given by
$f_{l i m} = μ_{s} N$
$= μ_{s} M g$
$= 0.5 \times 4 \times 10$
$= 20 N$
$f_{l i m} > F_{applied}$
If applied force is less than limiting friction, then friction force will be equal to applied force.
$f = F_{applied}$
$f = 12 N$