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Question

A block of mass 4 kg rests on a rough horizontal surface. If a horizontal force of 12 N is applied on the block, then the frictional force by the surface on the block is
(μk=0.4,μs=0.5 and g=10 m/s2)

A
16 N
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B
20 N
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C
12 N
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D
8 N
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Solution

The correct option is C 12 N
Limiting static friction is given by
flim=μsN
=μsMg
=0.5×4×10
=20 N
flim>Fapplied
If applied force is less than limiting friction, then friction force will be equal to applied force.
f=Fapplied
f=12 N

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