A block of mass m is pulled in the direction shown in the figure on a rough horizontal ground with a constant acceleration of magnitude a. The magnitude of the frictional force is:
A
Tcosθ−ma
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
μkmg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
μk(T−mg)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
μkTsinθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is ATcosθ−ma Let f be the frictional force. From FBD the equation of motion of the block , ma=Tcosθ−f⇒f=Tcosθ−ma Ans:(A)