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Question

A block of mass m is pulled in the direction shown in the figure on a rough horizontal ground with a constant acceleration of magnitude a. The magnitude of the frictional force is:
133677_42a7bb91fde14ee3b36ad974962ef5fe.png

A
T cos θma
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B
μkmg
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C
μk(Tmg)
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D
μk T sinθ
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Solution

The correct option is A T cos θma
Let f be the frictional force. From FBD the equation of motion of the block ,
ma=Tcosθff=Tcosθma
Ans:(A)
148101_133677_ans_0bf6da8c689447c9869bc754bdc8bfbe.png

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