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Question

A body A is dropped from a height h and the other body B is thrown horizontally with a velocity of 10ms1 from the same height simultaneously. If the time taken by the body to reach the ground is 3s, arrange the following steps in a proper sequence to find the velocity of the body B, in vertical direction when it is at a vertical height of 20m above the ground.
a) Find the displacement covered by the body B when it is at a height of 20m.
b) Calculate the vertical height from the ground from which both the bodies are falling from t=0
c) Write the required equation of motion and calculate the velocity at the given point.
d) Analyse the relation between the motions of two bodies.

A
d c a b
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B
d b a c
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C
a b c d
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D
d b c a
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Solution

The correct option is C d b a c
(i) The vertical motion of a horizontal projectile is same as that of a freely falling body.
The time taken to reach the ground for the horizontal projectile t=3s.
(ii) The vertical height from the ground h=12gt2=12×10×32=45m
h=12gt2=12×10×32=45m
(iii) The displacement covered by B when it is at a height of 20m from the ground,
h1=4520=25m
(iv) V2=u2+2gh1
V2=2×10×25=500
V=500=105ms1
Therefore the order is d b a c.

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