Question

A body executing S.H.M has a maximum acceleration equal to $48$ m$/{\sec }^2$ and maximum velocity equal to $12$ m/$\sec$. The amplitude of S.H.M is?

• A. $3$ m
• B. $3/32$ m
• C. $1024/9$ m
• D. $64/9$ m

Answer 1

The correct option is A $3$ m

Form maximum velocity ${\text{v}}_{max}=A\omega ;$=12 m/s

and from maximum acceleration ${\text{a}}_{max}=A{\omega }^2$=48 $m/s^2$

where A is the amplitude of SHM.

Putting the value of $\omega$=$\frac{12}{A}$ in maximum acceleration we get ,

$\frac{144}{A^2}\times A=48A=\frac{144}{48}=3$ m